[프로그래머스/C++] 010_문자열 겹쳐쓰기

문제 설명

문자열 my_string, overwrite_string과 정수 s가 주어집니다. 문자열 my_string의 인덱스 s부터 overwrite_string의 길이만큼을 문자열 overwrite_string으로 바꾼 문자열을 return 하는 solution 함수를 작성해 주세요.

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제한사항

my_string와 overwrite_string은 숫자와 알파벳으로 이루어져 있습니다.
1 ≤ overwrite_string의 길이 ≤ my_string의 길이 ≤ 1,000
0 ≤ s ≤ my_string의 길이 - overwrite_string의 길이

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입출력 예

my_string	overwrite_string	s	result
"He11oWor1d"	"lloWorl"	2	"HelloWorld"
"Program29b8UYP"	"merS123"	7	"ProgrammerS123"

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입출력 예 설명

입출력 예 #1

예제 1번의 my_string에서 인덱스 2부터 overwrite_string의 길이만큼에 해당하는 부분은 "11oWor1"이고 이를 "lloWorl"로 바꾼 "HelloWorld"를 return 합니다.

입출력 예 #2

예제 2번의 my_string에서 인덱스 7부터 overwrite_string의 길이만큼에 해당하는 부분은 "29b8UYP"이고 이를 "merS123"로 바꾼 "ProgrammerS123"를 return 합니다.

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코드

#include <string>
#include <vector>

using namespace std;

string solution(string my_string, string overwrite_string, int s) {
    string answer = "";
    int my_string_l = my_string.length();
    int overwrite_string_l = overwrite_string.length();
    
    if(1 <= my_string_l <= overwrite_string_l <= 1000){
        if(0 <= s <= my_string_l - overwrite_string_l){
            answer = my_string.replace(s,overwrite_string_l,overwrite_string);
        }
        else {
            answer = "error";
        }
    }
    else {
        answer = "error";
    }
    
    return answer;
}